用Jersey构建RESTful服务1--HelloWorld

一、环境

1. Eclipse Juno R2
2. Tomcat 7
3. Jersey 2.x(最新2.11版本测试通过) 下载地址（ https://jersey.java.net/download.html）

二、流程

1. Eclipse 中创建一个 Dynamic Web Project ,本例为“RestDemo”

2. 按个各人习惯建好包，本例为“com.waylau.rest.resources”

   

3. 解压jaxrs-ri-2.7，将api、ext、lib文件夹下的jar包都放到项目的lib下；

   

   项目引入jar包

   

4. 在resources包下建一个class“HelloResource”

    package com.waylau.rest.resources;
       import javax.ws.rs.GET;
       import javax.ws.rs.Path;
       import javax.ws.rs.Produces;
       import javax.ws.rs.PathParam;
       import javax.ws.rs.core.MediaType;
       @Path("/hello")
       public class HelloResource {
           @GET @Produces(MediaType.TEXT_PLAIN)
           public String sayHello() {
               return "Hello World!" ;
           }
   
           @GET @Path("/{param}")
           @Produces("text/plain;charset=UTF-8")
           public String sayHelloToUTF8(@PathParam("param") String username) {
               return "Hello " + username;
           }
   
       }
   

5. 修改web.xml,添加基于Servlet-的部署

   <servlet>
       <servlet-name>Way REST Service</servlet-name> <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
       <init-param>
       <param-name>jersey.config.server.provider.packages</param-name>
       <param-value>com.waylau.rest.resources</param-value> </init-param>
       <load-on-startup>1</load-on-startup>
   </servlet>
   
   <servlet-mapping>
       <servlet-name>Way REST Service</servlet-name>
       <url-pattern>/rest/*</url-pattern>
   </servlet-mapping>
   

6. 项目部署到tomcat,运行

7. 浏览器输入要访问的uri地址 http://localhost:8089/RestDemo/rest/hello,输出Hello World!

   

   http://localhost:8089/RestDemo/rest/hello/Way%E4%BD%A0%E5%A5%BD%E5%90%97,输出Hello Way你好吗

   

参考：https://jersey.java.net/documentation/latest/user-guide.html

本章源码：https://github.com/waylau/RestDemo/tree/master/jersey-demo1-helloworld